feat(finance): 统一履约事实并改造人工账单分类
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@@ -0,0 +1,89 @@
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import process from 'node:process'
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import { closeDb, query } from '../src/db/client.js'
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import {
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getFulfillmentModeCounts,
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reconcilePendingFulfillmentModes,
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syncOpenCostExceptionCarrierTypes,
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} from '../src/services/fulfillment/fulfillment-mode-service.js'
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const options = parseOptions(process.argv.slice(2))
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const batchSize = normalizeInteger(options.batchSize, 5000, 1, 50_000)
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const maxBatches = normalizeInteger(options.maxBatches, 1000, 1, 10_000)
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async function main() {
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const column = await query<{ exists: boolean }>(
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`
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SELECT EXISTS (
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SELECT 1
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FROM information_schema.columns
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WHERE table_schema = 'public'
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AND table_name = 'order_items'
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AND column_name = 'fulfillment_mode'
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) AS exists
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`,
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)
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if (!column.rows[0]?.exists) {
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throw new Error('order_items.fulfillment_mode 不存在,请先执行 npm run db:migrate(迁移 114)')
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}
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const startedAt = Date.now()
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const result = await reconcilePendingFulfillmentModes({
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batchSize,
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maxBatches,
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reason: 'backfill_2026_10_23',
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})
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const exceptions = await syncOpenCostExceptionCarrierTypes()
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const counts = await getFulfillmentModeCounts()
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console.log(
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JSON.stringify(
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{
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...result,
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exceptionCarrierUpdated: exceptions.updatedCount,
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batchSize,
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maxBatches,
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counts,
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durationMs: Date.now() - startedAt,
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},
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null,
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2,
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),
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)
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if (result.remainingCount > 0) {
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console.error(`仍有 ${result.remainingCount} 个订单项未回填;请增大 --max-batches 或检查数据。`)
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process.exitCode = 2
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}
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}
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main()
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.catch((error) => {
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console.error(error instanceof Error ? error.message : error)
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process.exitCode = 1
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})
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.finally(async () => {
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await closeDb()
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})
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function parseOptions(args: string[]) {
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const result: Record<string, string> = {}
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for (const arg of args) {
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if (!arg.startsWith('--')) continue
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const body = arg.slice(2)
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const index = body.indexOf('=')
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if (index === -1) {
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result[body] = 'true'
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} else {
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result[body.slice(0, index)] = body.slice(index + 1)
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}
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}
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return result
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}
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function normalizeInteger(value: unknown, fallback: number, min: number, max: number) {
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const parsed = Number(value)
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if (!Number.isInteger(parsed)) return fallback
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return Math.min(max, Math.max(min, parsed))
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}
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